Convert decimal to octal number in C, C++, Java and Python
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Convert decimal to octal number in C, C++, Java and Python
Program to convert a number from decimal to octal is discussed here. Given a decimal number as input, which has to be converted to its equivalent octal number.
For example, decimal number 200 has to be converted to octal.
200 / 8 = 25 , rem = 0
25 / 8 = 3 , rem = 1
3 / 8 = 0 , rem = 3
The equivalent octal number of the decimal number 200 is 310.
Algorithm to convert a number from decimal to octal
Input the decimal number.
Divide the decimal number by 8.
Store the remainder.
Repeat steps 2 and 3 until the number can be divided.
Print the reverse of the remainder, which is the octal equivalent of the decimal number.
Program to convert a number from decimal to octal
C
#include
#include <math.h>
int decimal_to_octal(int decimal);
int main()
{
int decimal;
printf(“\nEnter a decimal number: “);
scanf(“%d”, &decimal);
printf(“\nEquivalent octal number : %d\n”, decimal_to_octal(decimal));
return 0;
}
int decimal_to_octal(int decimal)
{
int octal = 0, i = 1;
while (decimal != 0)
{
octal += (decimal % 8) * i;
decimal /= 8;
i *= 10;
}
return octal;
}
C++
#include
#include <math.h>
using namespace std;
int decimal_to_octal(int decimal)
{
int octal = 0, i = 1;
while (decimal != 0)
{
octal += (decimal % 8) * i;
decimal /= 8;
i *= 10;
}
return octal;
}
int main()
{
int decimal;
cout << “\nEnter a decimal number: “;
cin >> decimal;
cout << “\nEquivalent octal number : ” << decimal>
cout << endl>
return 0;
}
JAVA
import java.util.*;
public class Main
{
public static int decimal_to_octal(int decimal)
{
int octal = 0, i = 1;
while (decimal != 0)
{
octal += (decimal % 8) * i;
decimal /= 8;
i *= 10;
}
return octal;
}
public static void main(String[] args)
{
Scanner sc = new Scanner(System.in);
System.out.print(“Enter the decimal number : “);
int decimal = sc.nextInt();
System.out.print(“\nEquivalent octal number : ” + decimal_to_octal(decimal));
}
}
PYTHON 3
def decimal_to_octal(decimal):
octal = 0
i = 1
while (decimal != 0):
octal = octal + (decimal % 8) * i
decimal = int(decimal / 8)
i = i * 10;
return octal;
decimal = int(input(“Enter the decimal number : “))
print(“Equivalent octal number : “,decimal_to_octal(decimal))
Output
Input- Enter a decimal number:200 Output- Equivalent octal number :310
Time complexity: O(n)
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